If int is 2 bytes wide.What will be the output of the program?
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If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}



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2) What will be the output of the program in 16 bit platform (Turbo C under DOS)?

#include<stdio.h>
int main()
{
int fun();
int i;
i = fun();
printf("%d\n", i);
return 0;
}
int fun()
{
_AX = 1990;
}

3) What will be the output of the program?

#include<stdio.h>
int addmult(int ii, int jj)
{
int kk, ll;
kk = ii + jj;
ll = ii * jj;
return (kk, ll);
}
int main()
{
int i=3, j=4, k, l;
k = addmult(i, j);
l = addmult(i, j);
printf("%d %d\n", k, l);
return 0;
}

4) What will be the output of the program?

#include<stdio.h>
#include<stdlib.h>
int main()
{
int i=0;
i++;
if(i<=5)
{
printf("Study2Online");
exit(1);
main();
}
return 0;
}

5) What will be the output of the program?

#include<stdio.h>
int reverse(int);
int main()
{
int no=5;
reverse(no);
return 0;
}
int reverse(int no)
{
if(no == 0)
return 0;
else
printf("%d,", no);
reverse (no--);
}

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